Question
$\text { Show that } c_{p}-c_{v}=T\left(\frac{\partial P}{\partial T}\right)_{v}\left(\frac{\partial v}{\partial T}\right)_{P}$.
Step 1
Step 1: We recall the relationship for $C_{P}-C_{V}$, which is given by: \[C_{P}-C_{V}=-T\left(\frac{\partial V}{\partial T}\right)_{P}^{2}\left(\frac{\partial P}{\partial V}\right)_{T}\] Show more…
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Show that $c_{p}-c_{v}=T\left(\frac{\partial P}{\partial T}\right)_{U}\left(\frac{\partial U}{\partial T}\right)_{P}$
Show that $$ c_{v}=-T\left(\frac{\partial U}{\partial T}\right)_{s}\left(\frac{\partial P}{\partial T}\right)_{v} \text { and } c_{p}=T\left(\frac{\partial P}{\partial T}\right)_{s}\left(\frac{\partial U}{\partial T}\right)_{P} $$
Show that $$c_{v}=-T\left(\frac{\partial v}{\partial T}\right)_{s}\left(\frac{\partial P}{\partial T}\right)_{v} \text { and } c_{p}=T\left(\frac{\partial P}{\partial T}\right)_{s}\left(\frac{\partial v}{\partial T}\right)$$
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