00:01
This is a case of eccentric loading and the maximum stress maximum stress developed will be direct stress plus bending stress so direct stress is force divided by area as bending stress is mc divided by i let this equation v equation number one now now let us calculate the moment of an urs say about y x so it is iy this is equals to bd cube divided by 12 it will be equals to 6 multiplied by 4 q divided by 12.
00:39
This is 32 inch 2d power of 4.
00:44
Hence, now we will calculate the area.
00:47
The area is 3 plus 1 .5 plus 1 .5 multiplied weight 2 plus 2 plus 2.
00:57
This is equals to 24 inch square.
01:03
So the radius of gyrrace and about y -axis, this will be equal to square root of iy divided by area this is equal to square root of 32 divided by 24 will give us a value of 1 .154 inch now let us calculate the cylinderness ratio so it will be kl divided by r about y x now since the rod is fixed at one end and pinned at another end so the value of k will be 0 .7 multiplied by length is 10 feet which is equals to 10 multiplied by 12 inch divided by r we have calculated 1 .154 so this will give us a value of 72 .79 now since kl divided by r about y x is greater than 55 hence column is hence we can use the formula we can use formula of stress sigma allowable this will be equals to 54 ,000 divided by k l.
02:13
D .l divided by r whole square.
02:18
So let's put the value here it is equal to 54 ,000 divided by 72 .79 square.
02:26
It will give us a value of 10 .19 ksi.
02:33
Let us now calculate the maximum allowable eccentric load.
02:37
So we will use the following interaction formula direct direct stress that is force divided by area divided by the allowable direct stress or axial stress sigma allowable this plus the stress due to bending that is mc divided by a rx square divided by the bending allowable stress sigma b allowable so this will be equals to 1 now now we need to calculate i x this is going to be bd cube divided by 12.
03:16
So it is equal to 4 multiplied by 6 cube divided by 12...