Question
The 1,2 adduct and the 1,4 adduct formed by reaction of HBr with 1,3 -butadiene are in equilibrium at $40^{\circ} \mathrm{C}$. Propose a mechanism by which the interconversion of products takes place.
Step 1
The HBr molecule acts as an electrophile and the double bond of the butadiene acts as a nucleophile. The nucleophilic double bond attacks the hydrogen of the HBr, forming a bond and leaving a bromide ion. This results in the formation of a carbocation Show more…
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The reaction of 1,3 -butadiene with HBr is shown below. At $40^{\circ} \mathrm{C}$ the major product is the 1 . 4-addition product; however, at $-80^{\circ} \mathrm{C}$ the major product is the 1,2 -addition product. Which of the two products has a lower activation energy for formation? (a) 1,4 -addition product. (b) 1,2 -addition product. (c) The products have same activation energy. (d) The relative activation energy cannot be determined.
Hydrocarbons
Level II
The reaction of 1,3 -butadiene with HBr is shown below. At $40^{\circ} \mathrm{C}$ the major product is the 1 . 4-addition product; however, at $-80^{\circ} \mathrm{C}$ the major product is the 1,2 -addition product. Why are two products formed? (a) The carbocation intermediate allows delocalisation of the second double bond. (b) There are two double bonds present. (c) The fact that the carbocation is planar allows attack from both sides of the plane. (d) There are 2 moles of $\mathrm{HBr}$.
When 1,3 -butadiene reacts with one mole of HBr, two isolable products result. Propose a mechanism to explain this.
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