00:01
In this exercise, we have a color that has a massive 2 pounds that is attached to a spring that has a spring constant of 4 pound force per foot.
00:10
And the color is constrained to move vertically.
00:15
And the unstretched length of the spring is equal to 1 foot, as shown here in the figure in blue.
00:24
S is the vertical distance of the color c.
00:31
And we know that when s is equal to zero, that is when the spring is unstretched, the initial speed v0 of the color is equal to 15 feet per second.
00:44
And our goal is to find what is the velocity of the color after it travels a distance of one foot, so after s is equal to one foot.
00:55
So what we need in order to solve this exercise is the concept of elastic force.
01:06
So f, the elastic force, is equal to minus the spring constant k times delta x, where delta x is the distance between the stretched, i'm sorry, is the difference of length between the stretched spring, and the unstructured spring, and the unstraged, stretched spring.
01:36
So it's, i'm going to call it x minus x0, where x0 is the equilibrium position of the spring.
01:43
And this is the information we need in order to solve the exercise.
01:47
So let's apply this to our specific problem.
01:53
So we have that the color is constrained to move in the x direction, meaning that the pole to which the color is attached will exert vertical forces on the the color such that the color will not move in the y direction.
02:17
Okay, so we are, so we can work only with the forces that act in the horizontal direction.
02:29
So consider that this here is the color and the force that the spring exerts on the collar is in this direction shown here in the picture.
02:48
It points along the spring and points downwards.
02:54
That is, it points in the direction of restitution.
02:59
So it tries to bring the collar back to the unstretched position.
03:05
And the horizontal force, horizontal component of this force is pointing in this direction here.
03:19
And it makes a certain angle of theta.
03:22
With the force itself.
03:24
So the horizontal component of the force f x is equal to the elastic force f times the cosine of theta and we saw up here that the cosine of theta is equal to s divided by the square roots of s squared plus one.
04:02
Also the force itself is equal to minus k, that is a spring constant, times the final position of the spring, i'm sorry, the final length of the spring, which is the square root of s squared plus one.
04:25
This is just pythagoras theorem.
04:27
I'm calculating the hypothesis here as a function of the lags minus the unstretched position of the spring, which is one foot...