00:01
All right, so for today's problem, we have an adventurer who is trying to cross these two cliffs.
00:07
So this over here is a cliff and so is this.
00:10
And he is sitting right here on a rope in the middle of the two cliffs, which is halfway in between.
00:18
So first, we are asked, what is the tension in the rope? so for that, we should first draw a free body diagram where this is our climber.
00:26
And we have one force pointing downwards, which is the force.
00:30
Of gravity, mg, and then over here we have two components to the rope.
00:35
We have one going to the left and one going to the right, both pointing slightly upwards.
00:41
Now if we try to decompose this, you can see that we have t of x and we have t sub y, and this is for both of the component or for both of the tension forces.
00:56
Sorry, that is t sub x and this is t sub y.
00:59
And we don't really need to to write down newton's second law to find out that the t sub x's cancel out because the tensions are equivalent.
01:09
So we can go ahead and start by writing newton's second law for the motion in the y direction.
01:14
So we get s of y is equal to m a y and the forces in the y direction we have m g, which is going downwards and we have upwards we have two t and in the y direction and this is equal to 0...