00:04
Hi friends here we have to find displacement of a as given in the figure displacement is defined as summation of n into l upon a into e displacement of b point is f vc into lvc plus f cd into l cd divided by a e and displacement of a will be displacement of p plus fab and ab upon ae.
01:12
For equilibrium, summation of fy on ab must be 0, that is fab minus 10 is equal to 0.
01:34
So fab we will get 10 kilo newton.
01:41
Submission of f y along bc must be zero so f bc minus two into five sign of theta minus 10 is called to zero and sign of theta is four upon five from the figure so f bc you will get 18 kilo newton now submission of f y along cd must be v0.
02:27
So fcd minus 2 into 6, sign of 45 minus 2 into 5, cause of 4, sorry, 2 into 5, 4 upon 5, let me correct it, 2 into 5 and 2 4 upon 5 minus 10 is called to 0.
02:54
So fcd is 26 .486 kilo, maximum stress is equal to yield strength and yield strength is 345 foresty a 992 it is to be 345 megapascal so stress maximum is called to strength in cd and cd upon a so substituting the value 26 .485 into 10 to the power 3 newton upon area projection 80 into 10 to the power minus 6 meter square so it is to be equal to 331 .07 10 to the power 6 pascal or 331 .07 megapascal which is less than sigma y now displacement for both the points a and b elasticity is 200 giga pascal for steel a 992 so displacement of p e you can find 18 into 10 to the power 3 into 1 .5 plus 26 .485 10 to the power 3 to 0 .75 to the power 3 2 .75 divided by a, that is area projection 18 into 10 to the power minus 6 into e elasticity, 200 into 10 to the power 9...