00:01
Right, this question we are given a table of different count rates as well as the time.
00:12
So what we want to do over here is to plot a graph of long of the count rates over the time.
00:25
So we will take long count rates as our y -axis and our x -axis would be time.
00:41
And why are we doing this? because count rates is basically telling us the activity at that point in time.
00:49
And we know that activity is equals to the initial activity multiplied by exponential negative lambda.
01:01
Now if we take the natural log on both sides, we will get lon of a -0 -e -negative landa -t, which is equals to lone of a -0 plus lone of e negative lambda t.
01:25
Now lone of a -0 would be a constant plus negative lambda t, right, or just minus lambda t.
01:34
Now if we plot lone of a against t, t, what we will get is negative lambda will be our gradient of this graph, right, it will be a linear graph.
01:49
This is the gradient and long of a knot will be our y intercept.
02:01
And therefore, by plotting this graph, you will be able to find lambda as well as the initial activity.
02:14
Now let us plot the different points.
02:18
Right, so i'm going to plot for you, but what you should do is you take the table and you're going to take the lawn of all the count rates and then this will be your y points, plot them into x points and we should get a curve of something like this.
02:34
And i've drawn the blue line, which is the best fit line across the entire data points.
02:42
Right, so this is the best fit line.
02:43
Now to find what is the decay constant lambda, we will need to find what is our slope.
03:03
Alright, our gradient over here we can calculate by taking two different points.
03:10
So i'm going to take two points, one over here, and the other point i'm going to take is over here.
03:22
These points are exactly on the grid, so it is more complex.
03:26
Convenient, right? so this point over here is 8 .1, whereas the point over here on the right, so it is not 8, 1, it should be 1 8, right, x, y, and the point over here is 9, 6.
03:52
So the slope or the gradient, and we're looking at is just a negative 8 minus 6...