00:01
All right, so we're looking at the amount of water consumed each day by a healthy adult, which is normally distributed, and the mean is 1 .4.
00:14
And there's a health campaign that's promoting drinking at least two liters a day.
00:21
And a sample of 10 adults showed the following consumption right here.
00:29
So we want to conclude at this point in one significance level that the water consumption has increased from 1 .4.
00:40
So h0 is going to be that the mean is less than or equal to 1 .4.
00:51
And h1, the alternative is that new is greater than 1 .4.
01:02
Increased at the means greater than 1 .4.
01:05
That's already.
01:06
I would like to double check my size, make sure i have those correct.
01:08
And i've done it correct.
01:09
Good for me.
01:10
So we need to find the average of those values.
01:13
Well mean that the average is the function values and then we're going to do the sample standard deviation good in the critical value we need to state our decision our decision rule so we want to know let's see there's 10 adults so nine degrees of freedom at the point -01 significance level one -tail test 0 .01 nine degrees of freedom is going to be in this column right there 2 .1 that's critical value so we know is the t value greater than 2 .821? we can figure it out with our mean here minus the population mean divided by this sample senior deviation divided by the square root of the sample size 2 .927 so it's just greater than the critical value but still it follows our rule so we will reject null and we can say that the the water consumption has increased.
02:27
And we're going to interpret the p value or calculate and interpret the p value.
02:30
So 2 .92 is what you need to remember.
02:36
And nine degrees of freedom, 2 .92.
02:40
It's a one -tailed test...