Question
The angle between the radical axis and the line joining the centres of the circles $x^{2}+y^{2}+2 g x+2 f y+c=0$ and $x^{2}+y^{2}$ $+2 g_{1} x+2 f_{1} y+c_{1}=0$ is(a) $\frac{\pi}{3}$(b) $\frac{\pi}{2}$(c) 0(d) $\frac{\pi}{6}$
Step 1
The centers of these circles are $(-g, -f)$ and $(-g_{1}, -f_{1})$ respectively. Show more…
Show all steps
Your feedback will help us improve your experience
Goutam Chand and 59 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The circles $x^{2}+y^{2}-x-y=0$ and $x^{2}+y^{2}-x+y=0$ intersect at an angle (a) $\frac{\pi}{2}$ (b) $\frac{\pi}{3}$ (c) $\frac{\pi}{6}$ (d) $\frac{\pi}{4}$
The angle of intersection of the circles $x^{2}+y^{2}+2 a x=0$ and $x^{2}+y^{2}+2 b y=0$ at $(0,0)$ is (a) $\frac{\pi}{3}$ (b) $\frac{\pi}{4}$ (c) 0 (d) $\frac{\pi}{2}$
The arithmetic mean (AM) of the abscissae of points of intersection of the circle x^2 + y^2 + 2gx + 2fy + c = 0 with the x-axis is: A. g B. -g C. f D. -f
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD