Question
The area bounded by the circle $x^{2}+y^{2}=8$, the parabola $x^{2}=2 y$ and the line $y=x$ in $y \geq 0$ is(A) $\frac{2}{3}+2 \pi$(B) $\frac{2}{3}-2 \pi$(C) $\frac{2}{3}+\pi$(D) $\frac{2}{3}-\pi$
Step 1
The circle $x^{2}+y^{2}=8$ is centered at the origin with a radius of $\sqrt{8}$. The parabola $x^{2}=2y$ opens upwards with its vertex at the origin. The line $y=x$ is a straight line passing through the origin with a slope of 1. Show more…
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