00:01
So our goal is to find this shaded area here, which is called the loop in this curve.
00:09
The curve itself is called the folium of descartes.
00:15
Now, i want to do that.
00:17
The first thing we have to do is make a slight parameterization.
00:21
Y equal x times t.
00:24
We then plug that back into our original equation to get x cubed plus x cubed, t cubed equals 3 x squared t we can simplify that further and factor out that x cubed it's x cubed 1 plus t cubed equals 3 x squared t now we can solve this for x by dividing both sides by x squared 1 plus t cubed.
01:16
This gives us x equals 3t over 1 plus t cubed.
01:26
Notice that the value for y is just x times t.
01:31
So that means that y is 3t squared over 1 plus t cubed.
01:42
And one other thing, if i divide y over x over x, i get 3t squared over 1 plus t cubed times 1 plus t cubed over 3t, which simplifies the t.
02:02
So t equals y over x.
02:06
I'll change colors here.
02:09
The next step is to differentiate this entire function with respect to t.
02:15
So we get d t over d t equals now we have a quotient rule so d y that's supposed to be y d t and x x y d x d x squared d t over d t over d t is one so i have d y and x d x y over d t b t that should be an x squared x squared and multiply both sides by x squared and we get x squared equals d y x b t x d x b t and d x y over d t now i'll change color again so it's follow along we take this x squared value and we plug in our x equals 3t over 1 plus t cubed value and that gives us 9 t squared over 1 plus t squared squared multiplied both sides by d t and equals x d y minus y d x x x x x x x minus y d x x x x x x x x x x x x x x x x x x x x x x x x x x x x x...