Question
The area of the plane region bounded by the curves $x+2 y^{2}=0$ and $x+3 y^{2}=1$ is equal to(A) $5 / 3$(B) $1 / 3$(C) $2 / 3$(D) $4 / 3$
Step 1
We can do this by setting the two equations equal to each other: \[x+2y^{2}=x+3y^{2}-1\] Solving this equation gives us \(y^{2}=1\), so \(y=1\) and \(y=-1\). Show more…
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