00:01
Okay, another giant problem.
00:03
So the thermal conductivity of a solid whose density and specific heat are known can be determined from the relationship k equals the thermal diffusivity times the density times divided by the density and divided by specific heat.
00:21
After evaluating the thermal diffusivity alpha.
00:27
We're going to consider a 2 centimeter diameter cylindrical rod.
00:33
It's made of a material that is a density of 3 ,700 kilograms per meter cubed and a specific heat of 920 joules per kilogram kelvin.
00:44
It's initially at a uniform temperature of 25 and there's two thermal couples, one in the center and one on the surface.
00:52
This is dropped into boiling water and after three minutes, the surface and center temperatures are 93 and 75 respectively.
01:01
And we're asked to find the thermal diffusivity and thermal conductivity of the material.
01:06
Okay, so let's, there's some charts we're going to use, and we're going to have to calculate this over, okay, r is equal to ro, and that is equal to 0 .01 meters.
01:53
So r over r equals 0.
02:02
Theta over theta 0 would be 93 minus 100 and 75 minus 100...