00:01
In this exercise, we have a ruby laser that, as we saw in the last exercise, has a wavelength of 694 .3 nanometers.
00:09
And the light from the laser passes through a circular aperture with a diameter of 5 millimeters.
00:19
And our go in question a is to find the angular spread theta of the beam after it passes through the aperture, considering that when it does, the laser beam is diffractive.
00:37
So here, in highlighted in red, we have the equation for the diffraction of light when it passes through a circular aperture.
00:51
And we have that a, which is the diameter of the aperture times sine theta is equal to 1 .22 times the wavelength of the lines.
01:06
So the sign of theta is 1 .22 times lambda divided by a.
01:16
This means that theta is the arc sign of 1 .22 times lambda.
01:24
Lambda is 6994 .3 nanometers or 6 .43 times 10 to the minus 7 meters divided by a, which is 5 millimeters, or 5 times 10 to the minus 3 meters.
01:41
So the angle theta is equal to 0 .000169 radiance, which is the same as 0 .0097 degrees...