Question
The beam is slit longitudinally along both sides as shown. If it is subjected to an internal shear of $V=250 \mathrm{kN}$ compare the maximum shear stress developed in the beam before and after the cuts were made.
Step 1
The moment of inertia is given by the formula: \[I = \frac{bh^3}{12}\] where b is the base and h is the height of the cross section. In this case, we are given that the moment of inertia is \(98.177 \times 10^{-6}\) m\(^4\). Show more…
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The beam is slit longitudinally along both sides. If it is subjected to a shear of $V=250 \mathrm{kN}$, compare the maximum shear stress in the beam before and after the cuts were made.
The beam is to be cut longitudinally along both sides as shown. If it is made from a material having an allowable shear stress of $\tau_{\text {allow }}=75 \mathrm{MPa}$, determine the maximum allowable internal shear force $\mathbf{V}$ that can be applied before and after the cut is made.
The beam is to be cut longitudinally along both sides as shown. If it is made from a material having an allowable shear stress of $\tau_{\text {allow }}=75$ MPa, determine the maximum allowable shear force $\mathbf{V}$ that can be applied before and after the cut is made.
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