00:01
In this question we learn about some basic concept of the newton's loss of motion.
00:04
The question is there are two blocks which are attached with the strings and the tensions are t1 and t2 respectively.
00:12
We have to find when the system is in equilibrium with a constant horizontal force mg acting on the point block c.
00:22
So we have to find 10 teta 1 and t2, t1 and t2.
00:28
Now to solve this question we can first draw the free for the diagram for the two blocks.
00:35
So for the block c, the forces which are acting is f, that is equal to mg, and there is a tension force t2.
00:57
The components of the tension force would be horizontal and vertical, that is t2, cost theta 2, where this angle is is tata 2.
01:16
Similarly for the block b the forces that are acting are acting are t1 and t2 and in this case the gravitational force that is equals to mg similarly in this case we will have the net force mg plus t2 cause kata 2 where this angle is keta 2 and this would be t1 cause kata 1 right so we have drawn the freeboard diagram...