We know that the shear stress formula is given by $\tau = \frac{VQ}{It}$, where $V$ is the shear force, $Q$ is the first moment of area, $I$ is the moment of inertia, and $t$ is the thickness.
Given that $V = 2$ kip, $Q_B = 3.75$ in$^3$, $I = 23.231$ in$^4$, and
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