00:01
In this question, we are given this circuit arrangement.
00:05
So there are two springs.
00:07
Each spring is connected to the to one plate of the parallel plate capacitor.
00:12
So in the voltage of the battery is 100 volts.
00:21
D is given to be 8 m m.
00:25
C is equal to 2 micro ferret when switch is open.
00:32
We are told that the distance between the plates decreased by half when the switch is closed.
00:41
So we want to find the charge on each plate and the spring constant of each spring.
00:48
So to solve this question in part a, so when switch is closed, d is decreased by a vector of 0 .5.
01:13
So the new d or the d prime is half of 8 m m is equal to 4 m.
01:23
And the parallel plate capacitor, the formula, using c equals to f0 .a with d.
01:31
Okay, when d decrease, when d decreases by a factor of 0 .5, c increases, c increases, c increases, this by two types...