00:01
In this question we have given a ball which is revolve in a horizontal plane and it is tied with a cord and this cord makes an angle of 30 degree with the vertical and we have to find the speed of the ball.
00:14
So first of all i'm going to draw the diagram for this given cushion.
00:17
So this is the cord we have to give on and this angle is 30 degree and we have given the length of the cord that is 1 .5 meter and this is the ball which revolves in this horizontal plane.
00:40
Let this is the radius of this circular path so this is let r so r will be 1 .5 of sine 30 and we have given the mass of this ball that is 0 .5 kg so first of all i'm writing the given data for this tuition so we can say that mass of the ball is 0 .5 kg and the angle that is theta is given to us which is 30 degree so in the first part of the problem we have to find the speed let this is is v.
01:13
So i'm going to draw the free body diagram of this ball.
01:17
So this is our ball and this is the cord and this angle is 30 degree from vertical.
01:30
So one is the weight of this ball which is acting vertically downward that is 0 .5 times of g and when force is the tension force in this chord.
01:38
So component of this tension force in this direction is given by and one is in vertical direction.
01:46
So this is p sine 30.
01:51
And this will be t cost 30.
01:55
Now i'm going to equate force balance in x direction and y direction.
01:59
So we can say that net force in x direction will be mass into acceleration that is centripetal acceleration.
02:05
So this is t sine 30 will be equals to mass into centipater acceleration is v square by r.
02:13
This is our equation first...