00:01
Okay, now with the problem 101.
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In one -on -one, you have the combustion of 1 .75 milligram of geranium, and they reduce, and this reaction produced 499m.
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Carbon dioxide and 184 milligram of water.
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And the question here is you have to find the empirical formula of geranium, okay? and now, when you learn organic chemistry, and when the compound, they are burned, when the compound is burned.
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Usually if the compound, the hydrocarbon or compound contains carbon, hydrogen, and oxygen, the products always carbon dioxide and water.
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That's why they give you the whole amount of the compound.
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So after that you have to find the mass of carbon and mass hydrogen.
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You have to find the mass oxygen too.
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Now how can we do? let's see.
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First of all you have to convert all milligrams to gram.
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We had a reason to do this because later you have to find more.
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And now we convert first, so we save time.
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Okay? 175 milligram.
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You tie 10 power negative 3 grams.
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Divided 1 milligram, you will 5 .175 grams.
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And the same, you do similar for 499 carbon dioxide.
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This might be equal 0 .499 carbon dioxide.
01:54
And the same, 184 million of water, you get the same .184 gram of water.
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You had the same way to do like 1 .75 milligrams, okay? the same way to do conversion.
02:13
And now you have to find the mass of carbon and mass hydrogen in 499 and 1 .84 gram water.
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And now we get mass of carbon.
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And this might be equal.
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You see one more carbon dioxide equal one more carbon.
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In one more carbon dioxide got only one more carbon carbon so mass of carbon dioxide tie for mass of carbon and we have um no let me write low.
03:18
So we have 0 .1499 gram.
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Tye one more of carbon dioxide divided from the mass of carbon dioxide.
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Okay? and you see in one more carbon dioxide equal the more of carbon.
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And then we can time for mass of carbon here.
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Divide one.
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I have to continue one more step, huh? so we can show all of them...