Question
The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is $0.07 \%$ by mass. If a $20 \mathrm{g}$ sample of this fertilizer is dissolved in $2.0 \mathrm{L}$ of solution, what is the molarity of $\mathrm{Cu}^{2+} ?$
Step 1
Since the concentration of copper(II) sulfate is 0.07% by mass, we can calculate the mass of copper(II) sulfate in the sample as follows: \[0.07\% \times 20g = 0.014g\] Show more…
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