The coordinates of any point on the circle through the points $\mathrm{A}(2,2), \mathrm{B}(5,3)$ and $\mathrm{C}(3,-1)$ can be written in the form $(4+\sqrt{5} \cos \theta, 1+\sqrt{5} \sin \theta) .$ Then, the coordinates of the point $\mathrm{P}$ on $\mathrm{BC}$ such that $\mathrm{AP}$ is perpendicular to $\mathrm{BC}$ are
(a) $(-1,4)$
(b) $(4,1)$
(c) $(1,4)$
(d) $(2,3)$