00:01
So in this question, we're given the decomposition of nocl, and we're going to use the glazius -clyperion equation in order to solve for the activation energy.
00:25
So you can see that this relates the value of k, the rate constant, to the temperature, and the slope is represented by negative activation energy over r, the gas constant.
00:45
So k2 and t2 have to match up, k1 matches up with t1.
00:53
So we are going to plug in the values in the appropriate place, making sure that the temperature and decay match up.
01:03
And then we're going to solve for activation energy, which is going to be in joules because our value for the gas constant is in joules per kelvin times mole.
01:14
So we are then going to solve for the activation energy.
01:23
So then we want to report it in kilojoules per mole, so we're going to convert it to kilojoules.
01:30
So in order to do that, divide by 1 ,000...