Question
The decreasing order of acidic nature of perchloric acid, sulphuric acid and sodium bisulphate is(1) sulphuric acid $>$ sodium bisulphate $>$ perchloric acid(2) sodium bisulphate $>$ sulphuric acid $>$ perchloric acid(3) perchloric acid > sodium bisulphate $>$ sulphuric acid(4) perchloric acid > sulphuric acid $>$ sodium bisulphate
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The more stable the anion, the stronger the acid. Show more…
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The decreasing order of acidic nature of $\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{I})$, $\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{II})$, and $\mathrm{HClO}_{4}(\mathbb{I I})$ is a. $I>\|>$ III b. $I>I I I>I I$ c. $\mathrm{III}>\mathrm{I}>\mathbb{I I}$ d. \|\|$>\|>1$
\Lambdartange the following acids in the decreasing order of acid strength. $1.11 . \mathrm{SO}_{4}$ 2. $11_{3} \mathrm{PO}_{4}$ 3. $11 \mathrm{ClO}_{\text {A }}$ 4. $11 \mathrm{NO}_{3}$ (a) $4>2>3>1$ (b) $3>1>4>2$ (c) $1>3>4>2$ (d) $3>1>2>4$
The correct decreasing order for acid strength is: (a) $\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{FCH}_{2} \mathrm{COOH}>$ $\mathrm{CNCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}$ (b) $\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{CNCH}_{2} \mathrm{COOH}>$ $\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}$ (c) $\mathrm{CNCH}_{2} \mathrm{COOH}>\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>$ $\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}$ (d) $\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{CNCH}_{2} \mathrm{COOH}>$ $\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}$
Aldehydes, Ketones and Carboxylic Acids
Topic 2 : Preparation and Properties of Carboxylic Acids and its derivatives
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