Question
The density of water is $1.00 \mathrm{~g} / \mathrm{mL}$ at $4^{\circ} \mathrm{C}$. How many water molecules are present in $15.78 \mathrm{~mL}$ of water at this temperature?
Step 1
First, we need to find the mass of water in grams. We can do this by multiplying the volume by the density: Mass = Volume × Density Mass = 15.78 mL × 1.00 g/mL Mass = 15.78 g Show more…
Show all steps
Your feedback will help us improve your experience
Nicole Smina and 61 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The density of water is $1.00 \mathrm{~g} / \mathrm{mL}$ at $4^{\circ} \mathrm{C}$. How many water molecules are present in $5.81 \mathrm{~mL}$ of water at this temperature?
lonic and Covalent Compounds
Molar Mass
The density of water is $1.00 \mathrm{g} / \mathrm{mL}$ at $4^{\circ} \mathrm{C}$. How many water molecules are present in $2.56 \mathrm{mL}$ of water at this temperature?
The density of water is 1.00 g/mL at 4°C. How many water molecules are present in 6.25 mL of water at this temperature?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD