Question
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion $s=1 / t^{2}$ where $t$ is measured in seconds. Find the velocity of the particle at times $t=a, t=1, t=2,$ and $t=3$
Step 1
The velocity is the derivative of the displacement with respect to time. So, we need to find the derivative of the given function $s=1 / t^{2}$. Show more…
Show all steps
Your feedback will help us improve your experience
Bobby Barnes and 74 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion $ s = 1/t^2 $, where $ t $ is measured in seconds. Find the velocity of the particle at times $ t = a $, $ t = 1 $, $ t = 2 $, and $ t = 3 $.
Limits and Derivatives
Derivatives and Rates of Change
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion $s=1 / t^{2}$ where $t$ is measured in seconds. Find the velocity of the particle at times $t=a, t=1, t=2,$ and $t=3$ .
A particle moves in a straight line with the given velocity (in meters per second). Find the displacement and distance traveled over the time interval, and draw a motion diagram like Figure 3 (with distance and time labels). $$ v(t)=t^{-2}-1, \quad[0.5,2] $$
Integration
Net Change as the Integral of a Rate of Change
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD