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Problem

A 2.00 - and a $7.50-\mu \mathrm{F}$ capacitor ca…

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Problem 65 Hard Difficulty

The duration of a photographic flash is related to an $R C$ time constant, which is 0.100$\mu$ s for a certain camera. (a) If the resistance of the flash lamp is 0.0400$\Omega$ during discharge, what is the size of the capacitor supplying its energy? (b) What is the time constant for charging the capacitor, if the charging resistance is 800 $\mathrm{k} \Omega ?$

Answer

a) 2$\cdot 5 \mu F$
b) 2

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Physics 102 Electricity and Magnetism

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Chapter 21

Circuits, Bioelectricity, and DC Instruments

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Video Transcript

time constant for RC circuit is given by time. Constant is equal to our times. To see our is resistance and seeing his capacitance and we argument time constant which is 0.1 microseconds, 0.1 times 10 power negative six micro. The factor is 10 power neither to six. Resistance is 0.4 Capacitance can be calculated now by just following this algebra, which is 10 power negative seven divided by zero point 04 This is equal to 2.5 times 10 our negative six carat which is 2.5 micro fire it. So that's the capacitance we should use. Then in part, be questions asked what will be the time constant if the charging resistance was 800 killer or in this case again they reuse the same formula are times to see as we know are now is 800 killer over. So 800 times 10 power three times took capacitance is the same which is 2.5 micro fired. So this is equal to hers. 20. So 2000 times 10 power three negative c This is two seconds. Thank you

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