Question
The electric field within a cell membrane is approximately $8.6 \mathrm{MV} / \mathrm{m}$ and is essentially uniform. If the membrane is $18 \mathrm{~nm}$ thick, what's the potential difference across the membrane?
Step 1
The electric field (E) is given as $8.6 \mathrm{MV/m}$, which is equal to $8.6 \times 10^{6} \mathrm{V/m}$. The thickness of the membrane (d) is given as $18 \mathrm{nm}$, which is equal to $18 \times 10^{-9} \mathrm{m}$. Show more…
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