Question
The potential difference across a cell membrane is $-90 \mathrm{mV} .$ If the membrane's thickness is $10 \mathrm{nm},$ what is the magnitude of the electric field in the membrane? Assume the field is uniform.
Step 1
Step 1: The electric field (E) in a region can be calculated using the formula: \[E = \frac{\Delta V}{d}\] where \(\Delta V\) is the potential difference and \(d\) is the distance. Show more…
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