Question
The electrons in a particle beam each have a kinetic energy of $1.60 \times 10^{-17} \mathrm{~J} .$ What are the magnitude and direction of the electric field that stops these electrons in a distance of $10.0 \mathrm{~cm}$ ?
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The work done is also equal to the negative of the electric force times the distance, $-Fd$. This can be written as: \[W = -Fd = \Delta K\] Show more…
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Each of the electrons in a particle beam has a kinetic energy of $1.60 \times 10^{-17} \mathrm{J}$ . (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' move- ment) that will stop these electrons in a distance of 10.0 $\mathrm{cm}$ ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.
Each of the electrons in a particle beam has a kinetic energy of $1.60 \times 10^{-17} \mathrm{~J}$. (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of $10.0 \mathrm{~cm}$ ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.
The electrons in a particle beam each have a kinetic energy $K$. What are the magnitude and direction of the electric field that stops these electrons in a distance $d$ ?
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