00:01
We are given the equation of a cardioid and want to find its length.
00:06
So the first thing i want to do is rewrite our equation as 5 plus 5 cosine theta.
00:18
And i'm going to take its derivative d theta equals negative 5 sine theta.
00:29
That little common handy.
00:32
As you can see directly below it here i've written the formula for the length of a cardioid and we just have to plug in these numbers and chug.
00:45
So for the length of one cycle formula is specifically two times the integral from zero to pi times the square root of r squared which is five, five, theta squared plus negative 5 sine theta squared d theta.
01:24
I guess i'm going to carry out this multiplication to pi this integral is see 25 cosine squared theta plus 50 cosine theta plus 25 plus 25 x squared theta let's see one half power fee theta now if you look at this i can actually factor out these this 25 here since that's 5 squared that's going to give us 2 times 5 5 to scroll from 0 to pi of cosine squared theta plus 2, cosine theta plus 1 plus sine squared theta, 3 1⁄2, 0⁄2 power d theta, cosine squared data plus sine square theta equal 1.
03:02
So that helps us simplify it even more.
03:06
And this just becomes 10 times the integral square root 2, cosine, theta plus 1, which i can rewrite even one more time.
03:36
10, 0, pi, square root of 2 times square root of cosine of cosine, theta, theta, plus 1, d theta.
03:51
Now i have to use a tricking the metric identity.
03:57
A cosine of theta equal, oh, actually, excuse me, cosine of theta plus 1 equal 2, cosine squared theta over 2.
04:19
And i can plug that back in to our formula.
04:24
10 squared 2, 0 to pi, square root of 2, of 2 cosine squared theta over 2 d theta.
04:45
I can pull out the squared 2, since it's also a constant...