The equilibrium constant for the reaction $\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+1 / 2 \mathrm{O}_2(\mathrm{~g})$
is $\mathrm{K}_{\mathrm{c}}=4.9 \times 10^{-2}$. the value of $\mathrm{K}_{\mathrm{e}}$ for the reaction $2 \mathrm{SO}_2$ $(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ will be [2006]
(a) 416
(b) $2.40 \times 10^{-3}$
(c) $9.8 \times 10^{-2}$
(d) $4.9 \times 10^{-2}$