00:01
Problem we're going to use the law of cosines so go ahead and write that out so 0 .6 squared is equal to xa squared plus 0 .2 squared minus 2 xa we're going to multiply that by 0 .2 and multiply that by the cosine of our angle so that's our law of cosine so we can go ahead and rewrite this to kind of we want to get our delta xa in there and we also want to have it be solved for delta xa so if we do that we end up with the equation delta xa is equal to 0 .4 xa times the sign of the angle and that's going to be over top of 0 .4 times the cosine of the angle and then we're going to subtract 2xa so that's one of our equations we're going to use so when the the flywheel undergoes positive angular displacement.
01:25
Both the force and the couple moment are going to do negative work.
01:30
So knowing that, we know that our delta u is equal to zero.
01:42
So our equation that we'll need, since it's doing negative work, will be negative force times delta xa, and then minus the couple moment.
01:56
Times angular displacement is zero.
02:02
So this is the two equations that we will need.
02:04
So now we can substitute in our first equation right here that we've figured out into the second one.
02:11
So if we do that, we end up with the equation.
02:22
Make sure we've got plenty of room here.
02:24
So on top we have 0 .4 xa times the sign of the angle.
02:34
And then on the bottom we have 0 .4 cosine...