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The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate $K_{\mathrm{sp}}$ for each of the slightly soluble solids indicated:(a) TICl: $[\mathrm{T}]^{+} ]=1.21 \times 10^{-2} \mathrm{M},\left[\mathrm{Cl}^{-}\right]=1.2 \times 10^{-2} \mathrm{M}$(b) $\mathrm{Ce}\left(\mathrm{IO}_{3}\right)_{4} :\left[\mathrm{Ce}^{4+}\right]=1.8 \times 10^{-4} M,\left[\mathrm{IO}_{3}^{-}\right]=2.6 \times 10^{-13} \mathrm{M}$(c) $\mathrm{Gd}_{2}\left(\mathrm{SO}_{4}\right)_{3} :\left[\mathrm{Gd}^{3+}\right]=0.132 \mathrm{M},\left[\mathrm{SO}_{4}^{2-}\right]=0.198 \mathrm{M}$(d) $\mathrm{Ag}_{2} \mathrm{SO}_{4} :\left[\mathrm{Ag}^{+}\right]=2.40 \times 10^{-2} M,\left[\mathrm{SO}_{4}^{2-}\right]=2.05 \times 10^{-2} \mathrm{M}$(e) $\mathrm{BaSO}_{4} :\left[\mathrm{Ba}^{2+}\right]=0.500 \mathrm{M},\left[\mathrm{SO}_{4}^{2-}\right]=2.16 \times 10^{-10} \mathrm{M}$
a. $1.45 \times 10^{-4}$b. $8.23 \times 10^{-55}$c. $1.35 \times 10^{-4}$d. $1.18 \times 10^{-5}$e. $1.08 \times 10^{-10}$
Chemistry 102
Chapter 15
Equilibria of Other Reaction Classes
Chemical Equilibrium
Rice University
Drexel University
Lectures
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A liquid is a nearly incom…
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A liquid is a state of mat…
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Assuming that no equilibri…
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love one. This is Ricky and they were working on Problem 29. So we're gonna be calculating the KS piece, given these concentrations of a bunch of compounds. All right, So the let's first right, the disassociation equation, which we can turn into a kiss. People version. Now, this is really easy. All we have to do is plug in the concentrations that were given and solved. So here we get cast musical than 1.45 times 10 to the negative forth. Next, we're gonna be doing the same thing. It's association equation, Casspi. And don't forget that we have to put 1/4 or a power for up here because this is based on molar ratios. Expense are based on another ratios. And now we can just plug in Chuck and we get 8.23 times 10 negative five. Next up gonna do the exact same thing This association equation converted into a case the equation expression and plug in our values softer ke sp 1.35 times 10 before and we got two more. So the disassociation equation and to our kiss p expression plugging Shug and we get a value for Casspi. Yes. 1.18 Time stand negative. Last but not least, association equation. Convert that into our case. P expression. Chug and we get a case p value of one point. Oh H times have been negative. Now it's videos helpful and I'll see you in the next.
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