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The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated:(a) AgBr: $\left[\mathrm{Ag}^{+}\right]=5.7 \times 10^{-7} M,\left[\mathrm{Br}^{-}\right]=5.7 \times 10^{-7} \mathrm{M}$(b) $\mathrm{CaCO}_{3} :\left[\mathrm{Ca}^{2+}\right]=5.3 \times 10^{-3} M,\left[\mathrm{CO}_{3}^{2-}\right]=9.0 \times 10^{-7} M$(c) $\mathrm{PbF}_{2} :\left[\mathrm{Pb}^{2+}\right]=2.1 \times 10^{-3} M,\left[\mathrm{F}^{-}\right]=4.2 \times 10^{-3} M$(d) $\mathrm{Ag}_{2} \mathrm{CrO}_{4} :\left[\mathrm{Ag}^{+}\right]=5.3 \times 10^{-5} M, 3.2 \times 10^{-3} M$(e) $\operatorname{In} \mathrm{F}_{3} :\left[\operatorname{In}^{3+}\right]=2.3 \times 10^{-3} M,\left[\mathrm{F}^{-}\right]=7.0 \times 10^{-3} \mathrm{M}$

a. $3.25 \times 10^{-13}$b. $4.78 \times 10^{-9}$c. $3.7 \times 10^{-8}$d. $8.99 \times 10^{-12}$e. $7.89 \times 10^{-13}$

Chemistry 102

Chapter 15

Equilibria of Other Reaction Classes

Chemical Equilibrium

Drexel University

University of Toronto

Lectures

03:07

A liquid is a nearly incom…

04:38

A liquid is a state of mat…

04:29

The following concentratio…

04:10

Use the given molar solubi…

03:12

The following $K_{\mathrm{…

02:01

The solubility of an ionic…

04:31

Write solubility equilibri…

02:37

A solution is prepared hav…

04:50

Assuming that no equilibri…

05:47

05:43

Refer to the Ksp values in…

06:13

04:36

Calculate the concentratio…

01:56

05:32

01:58

The $\mathrm{Hg}^{2+}$ ion…

The solubility of two slig…

03:59

Use the appropriate values…

03:58

For each of the following …

04:58

Calculate the molar solubi…

That's problem. Number 28. Starting with auction. E saw the association Reaction for aging br can be represented us one more lady positive plus be on negative in equal concentration in the question. We are already provided with the concentration off both the products. So Gai SP will be equal to the concentration of products that is a Jeep positive multiplied with b R negative ion concentration substituting in the values that is 5.7. Multiply 10 days to one negative seven. There's to the power to because they both have same concentration. So the soul ability off a GBR will be three point to five multiplied to invest one negative 13. Using the same method was all all the options or option B. The reaction goes as calcium carbonate will gives calcium to positive plus c +03 Don't make it do. We are already provide for the concentration off body products. Multiplying that chaos people B equals two for you. 0.3 multiply 10 days to put negative three for culture and for carbonate, it's 9.0 10 days to go negative. Seven. The soul ability for the product is 4.78 10 days to one negative nine. We want to option C. Let me write the reaction. First, it's lead chloride, which gives let to positive plus two f negative substituting the values into the scalability formula. We have K S P equals for lead. We have concentration to 0.1 time Rest of one negative three multiplied For Florin it's 4.2 10 days to plan negative three rays to power too, because we have to Atoms multiplying the soul ability obtained this 3.7 multiply trendiest open negative eight walks in D We have Eiji toe CR or four which gives to wedgie positive, less chromium oxide. Let's give gai sp equals Why you 0.3 multiplied Tenders to one negative five is to power too on 3.2 Multiply to invest one negative three Solving the case. Peter No, Toby 8.99 Multiply 10 days to one Negative. Well, negative. Moving on to the last option Auction e, we have India. The association will give us i n three positive Most three f negative again using the GS before Milosevic is multiplying the concentration off rodders One tree generous to one negative three multiplied with certain point. Zito 10 days to one negative three days to power. Three. The Sol ability off the product turns out to be 7.89 multiplied 10 days to plan negative 13.

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