The frequency of output signal of LC oscillator circuit is 100 Hz with capacitance value 0.1 μF

Name: Problem 2613, Chapter 19: JEE Physics
Uploaded: 2021-10-04T20:11:58-08:00
Duration: 1 min 52 s
Channel: Aja S
Description: The frequency of output signal of LC oscillator circuit is 100 Hz with capacitance value 0.1 μF. If value of capacitance is taken as 0.2 μF, the frequency of output signal (A) decreases by (1 / √(2)) (B) increases by (1 / √(2)) (C) decreases by (1 / 2) (D) increases by (1 / 2)

step 1 Okay, the question is a transistor oscillator using a resonant circuit with an inductor L is the

Question

The frequency of output signal of LC oscillator circuit is $100 \mathrm{~Hz}$ with capacitance value $0.1 \mu \mathrm{F}$. If value of capacitance is taken as $0.2 \mu \mathrm{F}$, the frequency of output signal (A) decreases by $(1 / \sqrt{2})$ (B) increases by $(1 / \sqrt{2})$ (C) decreases by $(1 / 2)$ (D) increases by $(1 / 2)$

   The frequency of output signal of LC oscillator circuit is $100 \mathrm{~Hz}$ with capacitance value $0.1 \mu \mathrm{F}$. If value of capacitance is taken as $0.2 \mu \mathrm{F}$, the frequency of output signal
(A) decreases by $(1 / \sqrt{2})$
(B) increases by $(1 / \sqrt{2})$
(C) decreases by $(1 / 2)$
(D) increases by $(1 / 2)$

JEE Physics

StemEZ 1st Edition

Chapter 19, Problem 2613

Instant Answer

Solved by Expert Aja S

10/04/2021

Step 1

Given that the initial frequency is 100 Hz and the initial capacitance is 0.1 μF, we can write the equation as: 100 = 1 / (2 * π * √(L * 0.1 * 10^(-6))) Now, we need to find the value of L. Rearranging the equation, we get: L = (1 / (100 * 2 * π))^2 / (0.1 * Show more…

Show all steps

Thanks for your feedback!

The frequency of output signal of LC oscillator circuit is $100 \mathrm{~Hz}$ with capacitance value $0.1 \mu \mathrm{F}$. If value of capacitance is taken as $0.2 \mu \mathrm{F}$, the frequency of output signal (A) decreases by $(1 / \sqrt{2})$ (B) increases by $(1 / \sqrt{2})$ (C) decreases by $(1 / 2)$ (D) increases by $(1 / 2)$

Play audio

Feedback

Aja S and 93 other educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Effect of Capacitance Change on Frequency

Because the frequency in an LC oscillator is inversely proportional to the square root of the capacitance, increasing the capacitance will lower the frequency. For instance, if the capacitance is doubled, the frequency decreases by a factor of 1/?2. This relationship is crucial in predicting how modifications in the circuit's capacitance will impact the oscillator's output frequency.

LC Oscillator Frequency Formula

The LC oscillator operates based on the formula f = 1/(2??(LC)), where L is the inductance and C is the capacitance. This formula establishes that the oscillation frequency is inversely proportional to the square root of the product of the inductance and capacitance, meaning that changes in these components directly affect the frequency.

Please give Ace some feedback