Question
The function $y=2 x^{2}-\ln 4 x(x>0)$ has one minimum point. Find its first coordinate.
Step 1
The derivative of $2x^{2}$ is $4x$ and the derivative of $-\ln 4x$ is $-\frac{1}{x}$. So, the derivative of the function is $y'=4x-\frac{1}{x}$. Show more…
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