Question
The ground state energy of hydrogen atom is $-13.6 \mathrm{eV}$. The energy of second excited state of $\mathrm{He}^{+}$ion in $\mathrm{eV}$ is:(a) $-54.4$(b) $-3.4$(c) $-6.04$(d) $-27.2$
Step 1
6 \times \left(\frac{Z^2}{n^2}\right) \, \text{eV}\] where \(Z\) is the atomic number and \(n\) is the principal quantum number. Show more…
Show all steps
Your feedback will help us improve your experience
Shalini Tyagi and 95 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The ground state energy of hydrogen atom is $-13.6 \mathrm{eV}$. The energy of second excited state of $\mathrm{He}^{+}$ion in $\mathrm{eV}$ is: (a) $-54.4$ (b) $-3.4$ (c) $-6.04$ (d) $-27.2$
In a hydrogen atom, if energy of an electron in ground state is - 13.6 eV , then energy in the 2^nd excited state is A. - 1.51 eV B. - 3.4 eV C. - 6.04 eV D. - 13.6 eV
Energy of $\mathrm{H}$ -atom in the ground state is $-13.6 \mathrm{eV}$, hence energy in the second excited state is: (a) $-6.8 \mathrm{eV}$ (b) $-3.4 \mathrm{eV}$ (c) $-1.51 \mathrm{eV}$ (d) $-4.53 \mathrm{eV}$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD