Question
The hardness of water is reported as milligrams of calcium carbonate per liter of water. Calculate the quantity of sodium carbonate in grams needed to soften 10.0 L of water with a hardness of $255 \mathrm{mg} / \mathrm{L}$. (Hint: How much $\mathrm{Ca}^{2+}$ is present in the water?)
Step 1
The hardness of water is given as 255 mg/L. Therefore, in 10.0 L of water, the amount of calcium carbonate is $255 \, \text{mg/L} \times 10.0 \, \text{L} = 2550 \, \text{mg}$. Show more…
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