Question
The height of a helicopter above the ground is given by $h=3.00 t^{3},$ where $h$ is in meters and $t$ is in seconds. After $2.00 \mathrm{s},$ the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?
Step 1
The height is given by the equation \( h = 3.00 t^3 \). At \( t = 2.00 \) seconds, substitute \( t = 2.00 \) into the equation to find the height: \[ h = 3.00 \times (2.00)^3 = 3.00 \times 8.00 = 24.00 \text{ meters} \] Show more…
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