0 \times 10^{20} \mathrm{eV}$, and we know that the total energy of a particle is given by $E = mc^2 \gamma$, where $\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}$, $m$ is the mass of the proton, $v$ is the speed of the proton, and $c$ is the speed of light.
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