00:01
So in this question we are told that we have hydrogen gas that is collected over water at 30 degrees celsius.
00:10
So t1 is equal to 30 degrees celsius and the total pressure of p total is 732 mm.
00:28
And we are taught to calculate the partial pressure of hydrogen gas.
00:34
So what we need to do is to know that the p -tortar is the partial pressure of hydrogen gas plus partial pressure of water, since it is collected over water.
00:53
So we need to know what the partial pressure of water is at 30 degrees celsius.
01:00
So p -total is 732 millimeter mercury, then ph -2.
01:08
Plus partial pressure of water at 30 degrees celsius is 3 .1 .8 millimeter mercury.
01:40
Therefore, the partial pressure of hydrogen will be equal to 732 minus 31 .8 millimeter mercury.
01:58
That is 700 .2 mm mercury.
02:22
That is the partial pressure of hydrogen gas.
02:31
Then the next question wants us to say that if the total volume of gas collected is 7 to 2 mm liter that what is the mass of hydrogen gas that is collected.
02:47
So for this we need to to use the id gas equation pv is equals to nrt...