Question
The kinetic energy of a body with mass $ m $ and velocity $ v $ is $ K = \frac{1}{2} mv^2 $. Show that $$ \dfrac{\partial K}{\partial m} \dfrac{\partial^2 K}{\partial v^2} = K $$
Step 1
Using the formula $ K = \frac{1}{2} mv^2 $, we differentiate with respect to $ m $ to get: \[ \frac{\partial K}{\partial m} = \frac{v^2}{2} \] Show more…
Show all steps
Your feedback will help us improve your experience
Alan Ghazarians and 62 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The kinetic energy of a body with mass $m$ and velocity $v$ is $K=\frac{1}{2} m v^{2} .$ Show that $$\frac{\partial K}{\partial m} \frac{\partial^{2} K}{\partial v^{2}}=K$$
PARTIAL DERIVATIVES
Partial Derivatives
solve the given problems. The kinetic energy $E$ of a moving object is given by $E=\frac{1}{2} m v^{2}$ where $m$ is the mass (in $\mathrm{kg}$ ) and $v$ is the velocity (in $\mathrm{m} / \mathrm{s}$ ). Find $\frac{\partial E}{\partial m}$ and $\frac{\partial E}{\partial v}$
Partial Derivatives and Double Integrals
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD