00:01
In this problem, i drew a picture to indicate all the pertinent bits of information that are given.
00:07
So let's start with the object.
00:12
We're told that the object is at right angles to the optic axis and it's an arrow.
00:18
And we're given the height of 1 .5 millimeters.
00:22
And we're given s, which is the distance from the object to the vertex of this glass rod, that at 24 centimeters.
00:29
And we're told that we have paraxial rays that are basically illuminating this object and it's going to get refracted into this glass.
00:41
And we're asked to find the image distance, s -prime, and the image height, y -prime.
00:52
So i drew a figure here just to indicate how the image will look, and we can see podality from these two rays that are being refracted.
01:04
Well, this one is going straight to the center here, through the center of this glass rod where the radius of curvature is.
01:15
So it will go straight through.
01:18
However, this beam that's coming to the vertex will get diffracted.
01:22
So then where these two intersect is where my image will form.
01:28
And we have the annex of refraction of glass.
01:30
We have the radius of curvature.
01:35
Here we have an a, which is assumed to be here.
01:39
And now we're going to use equations 34 .11 and 1 -2 to find.
01:51
So from this one, we'll find s -primed...