Question
The length of subnermal to the curve $y=x^{2}$ at $(2, b)$ is(a) 28(b) 32(c) 96(d) 64 .
Step 1
The curve given is \( y = x^2 \). At \( x = 2 \), we can find \( b \) by substituting \( x \) into the equation: \[ b = 2^2 = 4. \] So the point is \( (2, 4) \). Show more…
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$$ \begin{array}{l}{\text { Multiple Choice Find the length of the curve described by }} \\ {y=\frac{2}{3} x^{3 / 2} \text { from } x=0 \text { to } x=8 . \quad \mathrm{}}\end{array} $$ $$ \begin{array}{ll}{\text { (A) } \frac{26}{3}} & {\text { (B) } \frac{52}{3}} & {\text { (C) } \frac{512 \sqrt{2}}{15}}\end{array} $$ (D) $\frac{512 \sqrt{2}}{15}+8$ $(\mathbf{E}) 96$
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Model Test
Model Test 1
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