The magnetic field of Earth can be approximated as the magnetic field of a dipole. The horizontal and vertical components
of this field at any distance $r$ from Earth's center are given by
$$B_{h}=\frac{\mu_{0} \mu}{4 \pi r^{3}} \cos \lambda_{m}, \quad B_{v}=\frac{\mu_{0} \mu}{2 \pi r^{3}} \sin \lambda_{m}$$
where $\lambda_{m}$ is the magnetic latitude (this type of latitude is measured
from the geomagnetic equator toward the north or south geomag-
netic pole). Assume that Earth's magnetic dipole moment has
magnitude $\mu=8.00 \times 10^{22} \mathrm{A} \cdot \mathrm{m}^{2}$ (a) Show that the magnitude of
Earth's field at latitude $\lambda_{m}$ is given by
$$B=\frac{\mu_{0} \mu}{4 \pi r^{3}} \sqrt{1+3 \sin ^{2} \lambda_{m}}$$
(b) Show that the inclination $\phi_{i}$ of the magnetic field is related to
the magnetic latitude $\lambda_{m}$ by $\tan \phi_{i}=2 \tan \lambda_{m} .$