Question
The masses of the blocks $A$ and $B$ are $m$ and $M .$ Between $A$ and $B$ there is a constant frictional force $F$, and $B$ can slide frictionlessly on horizontal surface (see Fig. $7.378$ ). $A$ is set in motion with velocity while $B$ is at rest. What is the distance moved by $A$ relative to $B$ before they move with the same velocity?a. $\frac{m M v_{0}^{2}}{F(m-M)}$b. $\frac{m M v_{0}^{2}}{2 F(m-M)}$c. $\frac{m M v_{0}^{2}}{F(m+M)}$d. $\frac{m M v_{0}^{2}}{2 F(m+M)}$
Step 1
The frictional force $F$ acts on both blocks, but in opposite directions. Therefore, we can write the equations of motion for both blocks as follows: For block A: $F = m a_A$ For block B: $F = M a_B$ Show more…
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A block of mass $m$ is placed on another block of mass $M$ which itself is lying on a horizontal surface (see Fig. 7.353). The coefficient of friction between two block is $\mu_{1}$ and that between the block of block $M$ and horizontal surface is $\mu_{2}$. What maximum horizontal force can be applied to the lower block so that the two blocks move without separation? $\mathbf{a}_{-}(M+m)\left(\mu_{2}-\mu_{1}\right) g$ b. $(M-m)\left(\mu_{2}-\mu_{1}\right) g$ c. $(M-m)\left(\mu_{2}+\mu_{1}\right) g$ d. $(M+m)\left(\mu_{2}+\mu_{1}\right) g$
A block of mass $m$ is placed on another block of mass $M$ which itself is lying on a horizontal surface. The coefficient of friction between two blocks is $\mu_{1}$ and that between the block of mass $M$ and horizontal surface is $\mu_{2}$. What maximum horizontal force can be applied to the lower block so that the two blocks move without separation? (a) $(M+m)\left(\mu_{2}-\mu_{1}\right) g$ (b) $(M-m)\left(\mu_{2}-\mu_{1}\right) g$ (c) $(M-m)\left(\mu_{2}+\mu_{1}\right) g$ (d) $(M+m)\left(\mu_{2}+\mu_{1}\right) g$
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