00:01
Okay, let's start with part 8.
00:07
Okay, for number one, remember that the sum of the probabilities of all possible outcomes in an experiment where we have all is equal to 1.
00:18
And in order to get the probability that it is brown, we'll just have to subtract the sum of the probabilities of the other colors, then subtract it from 1.
00:29
And so we'll have the probability that we get a brown is equal to 1 minus sum 0 .20 plus 0 .20 plus 0 .10 plus 0 .10 and plus 0 .10.
00:55
Which is equal to 1 minus 0 .70 or 0 .2.
01:05
Next.
01:05
Next, for number two, to solve for the probability that it is either a yellow or an orange, we'll use the addition to the group under the mutually exclusive events since the two events cannot exist at the same time of picking.
01:26
So we'll just have probability that it is either yellow or orange is equal to the probability that is yellow plus probability that is an orange which is equal to 0 .20 or 0 .10 equals 0 .30.
02:02
Next for number 3 now that the probability that it is not green means that you already get the probability of the complement green and by the complement rule we have the probability of not green or the probability of the complement of green so we'll put a superscript of c about green is equal to one minus the probability that we get a green that is one minus zero point ten equals zero point ninety and last for part a right remember that the only that only plain m &ms are involved in this experiment and we know that the probability that the event will not, that the event will occur if it is not included in the sample space is just zero.
03:05
Therefore the probability of getting a striped when in fact we only have plain m &m is zero.
03:18
Next for part b we have three eminemes that are picked in sequence.
03:29
So let us put it here.
03:35
So for part b, so for this one we'll use the multiplication with under independent events, that is the probability of these events will occur just equal to the product of the individual probabilities.
03:54
And so for number one, the probability that all of the three are brown okay so the probability that all are brown okay it's just equal to the probability that we get a brown times the probability that we get a brown for this second one and the probability that we get a brown for the third one so we just have to multiply them all we have 0 .30 times 0 .30 times 0 .30 equals 0 .027.
04:51
Next, for number 2, okay...