Question
The maximum value of $\frac{x^{2}-x+1}{x^{2}+x+1}$ for all real val- ues of $x$ is(a) $1 / 2$(b) 1(c) 2(d) 3
Step 1
Step 1: First, we rewrite the given expression as follows: \[S = \frac{x^{2}-x+1}{x^{2}+x+1} = 1 - \frac{2x}{x^{2}+x+1}\] Show more…
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Application of Derivatives
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For all real values of $x$, the minimum value of $\frac{1-x+x^{2}}{1+x+x^{2}}$ is (A) 0 (B) 1 (C) 3 (D) $\frac{1}{3}$
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