1 molar $\mathrm{HCl}(\mathrm{aq})$ at $25^{\circ} \mathrm{C}$ as 0.796. The activity ($a$) of $\mathrm{HCl}$ can be calculated using the formula:
$a = \gamma \cdot c$
where $c$ is the concentration of the solution.
Given that $c = 0.1 \, \mathrm{mol/L}$ and
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